Write thw equation of the line that it is perpendicular to y=7x-3 and passes through the origin

Equation of the line that it is perpendicular to y=7x-3 and passes through the origin is given by 7y + x = 0

Explanation:

  We have equation of line , y =7x -3, comparing it with y = mx +c

  So slope of line , m = 7

 We know that the product of slopes of perpendicular lines = -1

 So   m*Slope of perpendicular line = -1

        7* slope of perpendicular line = -1

        slope of perpendicular line = -1/7

 Given that the perpendicular line passes through origin (0,)0)

 We also know that equation of a line passing though origin is given by the expression, y = mx

 Here m = -1/7

 So equation of perpendicular line, y = -x/7

                   or      7y + x = 0

 Equation of the line that it is perpendicular to y=7x-3 and passes through the origin is given by 7y + x = 0

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

b

step-by-step explanation: