Let f(x)= 3x+5 and g(x)=3x^2-x-10. find (f/g)(x) and state its domain. a. 2x-3; domain is the set of all real numbers b. 1/x-2; domain is the set of all real numbers except 2 c. 3x+5; domain is the set of all real numbers d. 2x+3/x-1; domain is the set of all real numbers except 1

Option B

Step-by-step explanation:

Given that f(x) = 3x+5 and g(x) = 3x^2-x-10

Hence the function f/g = (3x+5)/(3x^2-x-10)

Since denominator cannot be 0 we have

3x^2-x-10 cannot be 0

i.e. x should not take values where 3x^2-x-10 =0

Solving (3x+5)(x-2) =0

x cannot take value as 2 or -5/3

So we can cancel 3x+5 and write

f/g =1/ x-2

Hence x cannot take values as 2

Option B

positive

step-by-step explanation:

the quadrant is facing upwards