One warehouse had 185 tons of coal, another one had 237 tons. the first warehouse delivered 15 tons of coal to its clients daily, the second one delivered 18 tons of coal to its clients daily. in how many days will the second warehouse have 1.5 times more coal than the first one? i need this in 5 mins

Given

 One warehouse had 185 tons of coal, another one had 237 tons

The first warehouse delivered 15 tons of coal to its clients daily, the second one delivered 18 tons of coal to its clients daily.

Find out in how many days will the second warehouse have 1.5 times more coal than the first one.

To proof

Let us assume that the number of days of delivered the coal = x

Take two cases

First case

As given in the question

One warehouse had  coal = 185 tons

The first warehouse delivered 15 tons of coal to its clients daily

(As first warehouse delivered 15 tons of coal to its clients daily than the total amount of coal decrease daily as days increase)

Than the equation becomes for first warehouse

= ( 185 - 15x)

( this equation represent the amount of coal left after x days)

Second case

second warehouse had  coal = 237 tons

the second one delivered 18 tons of coal to its clients daily.

(As first warehouse delivered 18 tons of coal to its clients daily than the total amount of coal decrease daily as days increase)

Than the equation becomes for the second warehouse

= ( 237 - 18x)

( this equation represent the amount of coal left after x days)

As given in the question

the second warehouse have 1.5 times more coal than the first one

Thus

( 237 -18x ) = 1.5× ( 185 - 15x)

237 - 18x = 277.5 - 22.5x

22.5x - 18x = 277.5 - 237

4.5x = 40.5

x = 9

Therefore  the second warehouse have 1.5 times more coal than the first one in 9 days.

Hence proved

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/