You have also set up a card game in which a player picks a card from a standard deck of 52 cards. the player wins if these two events occur together: e1, in which the card drawn is a black card, and e2, in which the card drawn is a numbered card, 2 through 10.what is the probability of getting a black card and a numbered card? calculate the probabilities p(e1) and p(e2) as fractions.

First, let's count:

there are 26 possible outcomes for E1 (black card)

there are 4x9 = 36 possible outcomes for E2, to pick a numbered card (any color)

there are 2x9 =18 possible outcomes for E1 (black) AND E2 (numbered, spade + clower)

the probability of E1 AND E2 is the ratio of the count of possible outcomes for E1 + E2 and the count of all possible outcomes (52 choices to pick a card from the deck):

P(E1 and E2) = 18/52 (34.6%)

And as asked:

P(E1) = 26/52 = 1/2 (50%)

P(E2) = 36/52 = 9/13 (69.2%)

EDMENTUM / PLATO ANSWER

CAN JUST WRITE:

=  (50%)

=  (69.2%) :)))))

ur mom

step-by-step explanation:

this answer is !