Plz will mark brainliest! if the quantity 4 times x times y cubed plus 8 times x squared times y to the fifth power all over 2 times x times y squared is completely simplified to 2xayb + 4xcyd, where a, b, c, and d represent integer exponents, what is the value of a? numerical answers expected!

a=0.

(4xy^3+8x^2y^5)/(2xy^2) (4xy^3+8x^2y^5)/(2xy^2)  Since 2xy^2 is a common factor we have

Go to do 2y+4xy^3

Then do 2y=2x^ay^b

Then Do x^0=x^a

Then, you'll get the answer of a=0.

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.