With geometry? find the distance between these given points, using the pythagorean theorem. d( 5,-6) e (2,3)

using the distance formula ( Pythagorean identity )

d = √(x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (5, - 6) and (x₂, y₂) = (2, 3 )

d = √ (2 - 5 )² + (3 + 6)² = √(9 + 81 ) = √90 = 3√10 ≈ 9.5 ( 1 dec. place)

If you plot the points on a graph, you will see that the distance on the x-axis is from 5 to 2 which equals 3 and the distance on the y-axis is from -6 to 3 which equals 9

Pythagorean Theorem:

a² + b² = c²   ; where c is the hypotenuse

3² + 9² = c²

9 + 81 = c²

90 = c²

√90 = √c2

3√10 = c

3√10 ≈ 9.5

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes