Ineed with a question before my test: how do i tell if a graph has rotational symmetry if it is not an odd function and do all odd functions have point symmetry? ?

If you know that the function is not odd, you know that the graph does not have rotational symmetry

Step-by-step explanation:

There is a theorem that says: "A function is odd if, and only if, its graph is symmetric with respect to the origin, or it has rotational symmetry in 180 ° with respect to the origin"

This statement is equivalent to:

If a function is odd, its graph has rotational symmetry with respect to the origin

If a graph has rotational symmetry with respect to the origin then the function is odd.

Therefore, it is impossible for the graph to have rotational symmetry with respect to the origin and the function is not odd.

Then, if you know that the function is not odd, you know that the graph does not have rotational symmetry

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.