How much interest is earned on an investment of $6000 at 3.5%annual interest after 6 months? how did my teacher get 105 i need

Solution

Here we have to use compound interest formula for half year.

6 months = 1/2 years

Amount =

R = Rate

P = Principle

n = number of years

Here P = 6000, r/2 = 3.5/2 = 1.75, n = 1/2

Plug in the given values into the formula, we get    

A  = 6000(1 + 1.75/100)^2(1/2)

A = 6000(1 + 0.0175)^1

A = 6000(1.0175)

A = $6105

Compound interest = A - P

= $6105 - $6000

Interest = $105

Thank you :)

answer: the answer is 23

step-by-step explanation:

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: