Hello could you answer the questions in the attachment about arc length and the area of a sector. show full working out.
(note i have provided 2 attachments both of the same sheet in case 1 isn't clear)

: )

Easy peasy
so remember that
1 ful roation=360 degrees
so
if you are given an arc of x degrees, that arc's area=x/360 of total area and the arc legnth=x/360 of circumference so

1. a. 60/360 times 10 times 2 times pi=(10pi)/3 cm
b. 60/360 times 10^2 times pi=(50pi)/3 cm^2

2. a. 120/360 times 5 times 2 times pi=(10pi)/3 cm
b. 120/360 times 5^2  times pi=(25pi)/3 cm^2

3.a. 45/360 times 2 times 2.4 times pi=0.6pi cm
 b. 1/8 times 2.4^2 times pi=0.72pi cm^2

4.a. 75/360 times 3.2 times 2 times pi=(4pi)/3 cm
b. (40.96pi)/3 cm^2

5.a.150/360 times 2 times 72 times pi=2pi cm
b.  72pi cm^2

6.a. 15/360 times 2 times 12 times pi=pi cm
b. 6pi cm^2

7.a. quarter is 1/4 so 1/4 2 pi 1.9=0.95pi cm
b. 0.9025pi cm^2

The decimal expansion would be .27 repeated

Idk what the answer is bc i don't get it