The sum of 5 consecutive integers is 110, what is the fourth number in this sequence?

The answer is:  " 23 " .

    →  The fourth number in the sequence is:  " 23 " .

Explanation:

To solve:

 " x + (x + 1) + (x + 2) + (x + 3)  + (x + 4) = 110 " ;

in which:

 "x" = The first number in these sequence;

 "(x + 1 )" = the second number in the sequence;

 "(x + 2)" = the third number in the sequence;

 "(x + 3)" = the fourth number in the sequence;

 "(x + 4)" = the fifth number in the sequence;

Solve for the "fourth number in the sequence" ; or:  "(x + 3)" ;

Given:  " x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 110 " ;

                     ↔   " x + x + 1 + x + 2 + x + 3 + x + 4 = 110 " ;

→  Solve for "x" ;  

→  then,  solve for "(x + 3)" ;  

     →  which is the fourth number in this sequence;

→  " x + x + 1 + x + 2 + x + 3 + x + 4= 110 " ;

      "5x + 1 + 2 + 3 + 4= 110 " ;

      " 5x + 10 =  110 " ;

Solve for "x" :

     Subtract "10" from EACH SIDE of the equation; as follows:

      " 5x + 10 - 10 =  110 - 10 " ;

 to get :

      "  5x = 100 " ;

Now, divide EACH SIDE of the equation by "5" ;

to isolate "x" on one side of the equation; & to solve for "x" ;  as follows:

         5x / 5  = 100 / 5 ;

to get:

         "  x  = 20 "  .

Now, to find the fourth number in the sequence:

 →  " (x + 3) " ;

→  Substitute "20" for "x" ;

    " x + 3 = 20 + 3 = 23" ;

The answer is:  " 23 " .

The fourth number in the sequence is:  " 23 " .

Let us check our work:

If there are five "5" numbers in the sequence, and "23" is the "fourth number" , then:  "24" is the "fifth number" .

As such:  "22" is the "third number" ;  "21" is the "second number" ; and "20" is the "first number" .  Is this consistent with:  "x = 20" as the "first number" ?  Yes!

Thus,  "20 + 21 + 22 + 23 + 25 = ?  110 ?  ? ;

→  20 + 21 = 41 ;

→  41 + 22 = 63 ;

→  63 + 23 = 86 ;

→  86 + 24 = 110 .    Yes!

Hope this answer is helpful!

Best wishes in your academic pursuits—

 and within the community!

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b - exponent

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