Given m∠d = 70°, m∠e = 42, and m∠ehg = 68°, prove df is parallel to gh.

we know that

If DF is parallel to GH

then

the measure of the angle EGH must be equal to 70° by corresponding angles

so

Find the measure of the angle EGH

In the triangle EGH

the sum of the internal angles must be equal to 180 degrees

42°+68°+∠EGH=180°

solve for ∠EGH

∠EGH=180-(42+68)

∠EGH=180-110

∠EGH=70°

therefore

The lines DF and GH are parallel

probably .5

i can on others if necessary.

measurement of the swimming pool is given as = 7 yards 4.79 feet

first we will convert this to yards only.

1 foot = 0.33 yards

so, 4.79 feet = yards

so total yards are = yards

now we will convert this in meters.

1 yard = 0.914 meters

8.580 yards = meters

0.842 m = 0.842*100 = 84.2 cm

this becomes 7 meters and 84.2 cm

hence, the pool is 7 meters and 84.2 cm wide.