Does the parabola with equation x2– x + 6 = 0 have real or imaginary roots?

imaginary roots

to check the nature of the roots of a parabola in standard form :

ax² + bx + c = 0 : ( a ≠ 0 ) use the discriminant b² - 4ac

• If  b² - 4ac > 0 then roots are real and distinct

• If b² - 4ac = 0 then roots are real and equal

• If b² - 4ac < 0 then roots are not real

for x² - x + 6 = 0 with a = 1, b = - 1, c =  6

b² - 4ac = ( -1)² - (4 × 1 ×  6 ) = 1 - (  24 ) = 1 - 24 = - 23

since b² - 4ac < 0 then roots are not real ( imaginary )

y = 0.77(x)

step-by-step explanation:

the jacket retains this value after 23% cut or retains 77% of original value. plug original 87 jacket price for x and the remaining value should be y.

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>