The slope intercept form of the equation of a line that passes through point (-2, -13) is y = 5x -3 what is the point slope form of the equation for this line? answers a. y - 13= 5(x-2) b. y+13=5(x+2) c. y - 2= 5(x-13) d. y+2=5(x+13)

The point slope equation for this line is y + 13 = 5(x + 2)

In order to find this, use the point-slope base form and plug in the point for (x1, y1) and the slope for m.

y - y1 = m(x - x1)

y - -13 = 5(x - -2)

y + 13 = 5(x + 2)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

the correct is answer is a 9-sided polygon!