If f(x)=2x+1 and g(x)=x^2-1, find (f/g)(x) a. x^2 - 7 / 2x + 1 b. 2x + 1 / x^2 - 7 c. 2x + 1 / x^2 - 7, x ≠ ± square root 7 d. x^2 - 7 / 2x + 1, x ≠ - 1/2

Given : f(x)=2x+1 and g(x)=x^2-1.

We need to find  (f/g)(x).

Note: In the given options, we have 2x + 1 and  x^2 - 7 parts.

So, let us take f(x)=2x+1 and g(x)=x^2-7.

Plugging f and g functions in the formula.

Also, it would be undefined for x = ± square root 7 becaue it would give 0 in the denomiantor.

Therefore, correct option is C. 2x + 1 / x^2 - 7, x ≠ ± square root 7.

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign