Ineed d: (the question is on the image! )

Remark

You have to make an assumption here. I know of no other way to do the problem than by making the assumption that 10 * 14 figure is a rectangle. If that is not true, the problem is not solvable.

Step One

Find the length of the shaded area.

The length will be the length of the hypotenuse of a right triangle formed by the two smaller sides = the hypotenuse.

a = 4

b = 12

c =

Length

L = square root (a^2 + b^2)

L = √(4^2 + 12^2)

L = √(16 + 144)

L = √160    =  √(4*4 * 10)

L = 4√(10)

Width

The width is done the same way.

a = 6

b = 2

w = c = ??

w = √(6^2 + 2^2)

w = √(36 + 4)

w = √40

w = √(2 * 2 * 10)

w = 2 √ 10

Area

Area = L * W

Area = 4√10 * 2√10

Area = 8 * 10

Area = 80

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.