Hellpp! antoine has $18.20 to spend on some oranges and a pumpkin. oranges cost $1. 30 and a pumpkin costs $5. 20. the inequality 1.30x + 5. 20 models this situation, where x is the number of pounds of oranges. solve the inequality. how many pounds of oranges can antonio buy? (the photo has the choices)

To solve this inequality, we have to isolate x on one side. Whatever we do to the equation we have to do it on both sides.

1.30x + 5.20 ≤ 18.20

Subtract 5.20 from both sides.

1.30x + 5.20 - 5.20 ≤ 18.20 - 5.20

1.30x ≤ 13

Divide by 1.30 on both sides.

1.30x/1.30 ≤ 13/1.30

x ≤ 10

Antoine can buy 10 pounds of oranges.

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

the number of the people going.

step-by-step explanation:

the cost to buy one movie ticket is $7. if the total cost for the movie is a function of how many people go, then the input is : the number of the people going.