Mathematics
Mathematics, 08.07.2019 06:00, claplo9141

Order the steps to solve the equation log3(x + 2) = log3(2x^2 βˆ’ 1) from 1 to 6. 0 = (2x βˆ’ 3)(x + 1) 0 = 2x^2 βˆ’ x βˆ’3 potential solutions are βˆ’1 and 3/2 2x βˆ’ 3 = 0 or x + 1 = 0 x + 2 = 2x^2 βˆ’ 1 3^log3(x + 2) = 3^log3(2x2 βˆ’ 1)

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Order the steps to solve the equation log3(x + 2) = log3(2x^2 βˆ’ 1) from 1 to 6. 0 = (2x βˆ’ 3)(x + 1)...

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