If f(x)=4-x^and g(x)=6x, which expression is equivalent to (g-f)(3)

f(x)=4-x^2 and g(x)=6x

find (g -f)(3)

We know (g - f)(x) = g(x) - f(x)

(g -f)(3) = g(3) - f(3)

LEts find g(3)

we know g(x) = 6x . so g(3) = 6(3) = 18

We know

(g -f)(3) = g(3) - f(3)  , we got g(3) = 18  and f(3) = -5

(g -f)(3) =  18 - (-5) = 18 + 5 = 23

(g-f)(3) = 23

Expression is (g-f)(3) = g(3) - f(3) =

-8

step-by-step explanation:

where's the diagrams?