Find two consecutive even integers such that 3 times the smaller integer is 16 more than twice the larger

n, n + 2 - two consecutive even integers

3n = 2(n + 2) + 16     |use distributive property

3n = (2)(n) + (2)(2) + 16

3n = 2n + 4 + 16

3n = 2n + 20     |subtract 2n from both sides

n = 20

n + 2 = 20 + 2 = 22

20, 22.

answer: 457.14

step-by-step explanation:

205 - 45 = 160

160 / .35 = 457.142857

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5