Mathematics, 08.07.2019 14:30, abalaam
How would you write the following expression as a single term? 3[2 ln(x-1) - lnx] + ln (x+1)
Answers: 1
![3[2 ln(x-1) - lnx] + ln(x+1)=3[ln(x-1)^{2} - lnx ] + ln(x+1)](/tpl/images/0065/9006/b3bda.png)
![3[2 ln(x-1) - lnx] + ln(x+1)=3ln\frac{(x-1)^{2} }{x} + ln(x+1)](/tpl/images/0065/9006/6a7ed.png)
![3[ln (x-1)^{2} -ln x]+ln (x+1)= ln \frac{(x-1)^{6} }{x^{3} } +log(x+1)](/tpl/images/0065/9006/31821.png)
![3[ln(x-1)^{2} -ln x]+log(x+1)=ln\frac{(x-1)^{6}(x+1) }{x^{3} }](/tpl/images/0065/9006/4c40e.png)
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How would you write the following expression as a single term? 3[2 ln(x-1) - lnx] + ln (x+1)...
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