It's asking me to find an equation for the line i drew but i don't know how, and i'm not even sure if my line is correct.

This sort of problem doesn't have one right answer. All that is required is that your answer be consistent: the line and the equation should match, and should be "reasonably close" to the data.

Your graph is a bit funny in that most vertical squares are marked as representing 10 units, but the first one is marked as 5. That's OK if you consider zero to be in the middle of the first square the way multiples of 10 are in the middle of squares above that. Most folks would expect the squares to be labeled 0 (at the bottom), then 10, 20, 30, and so on.

If you look at the first two data points, they are proportional with a slope of 15/2 = 30/4. However, the next two data points are not. It looks like you have drawn your line (and it should be a straight line—as with a ruler) through the first and last data points. If so, you can use those two points to find the equation.

The slope between them is ...

... (difference of y-values)/(difference of x-values) = (65 -15)/(8 -2) = 50/6 = 25/3

Then, the point-slope form of the equation of a line can be used. For slope m, the line through point (h, k) can be written as

... y = m(x -h) +k

If you use the first point and the slope calculated above, this becomes

... y = (25/3)(x -2) +15

... y = (25/3)x -(5/3) . . . . simplified

where y is the breaking weight in pennies and x is the number of layers.

You will note that this line has a negative y-intercept. That is, a bridge with 0 layers is broken already. Of course, a bridge with 0 layers does not exist, so the domain of your equation would be for 2–8 layers (or so—covering the data you have, and maybe allowing for a little extrapolation).

Another way to draw the line is to give it a slope that matches the slope between the first two points and the last two points (y-difference of 15 for x-difference of 2), but has a slight positive offset to better match the last two points at the expense of matching the first two points. Such a line might have the equation

... y = (15/2)x +(5/2)

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

answer: yes i agree that you should not put it on/p>

step-by-step explanation: the reason for this is that it wastes other peoples time and also make them fail as well and that is never good.