By what percentage did the median earnings of college degreed exceed that of high school degreed for 1973 for men (to the nearest % by what percentage did the median earnings of college degreed exceed that of high school degreed for 1967 for women (to the nearest %

Remark

I'm going to state what I think the question is saying. I'm having a little trouble figuring it out.

1. Both groups are from 1967.

2. Both groups are women?

It's actually clear, but I had to restate it to get it clear for me.

Solution

Givens

College: Women= 4400

H.School: Women = 3300

Solve

The base number is the high  school women.

The difference is 4400 - 3300 = 1100

So the % = (1100/3300) * 100% = 33.3%

1973

I did this in the wrong order, but it will still give you the right answer.

The base number is again high school: 5600

Difference: 6600 - 5600 = 1000

% = (1000/5600) * 100% = 17.9

Comment

What this means is that if you take the % difference and multiply it by the smaller number you get the actual difference between the 2 groups.  Put another way, for the 1973 group, the college women made 17.9 % more than the high school group. As an aside, there are lots of reasons for this and I'm not certain it is any longer true.

its the fourth option

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,