Acylinder with a 10 inch bore and a 24in stroke must move a 78540 lb load through its truck in 3 seconds how much hydraulic horsepower must be delivered to the cylinder?

We are given that the stroke is 24 inches. Therefore, the distance travelled will be given by inches.

Now, the force given to us is lb.

Therefore, the work done will be:

lb-in.

Now, Let "P" be the power and "t" be the time.

The time, t given to us is t=3 seconds.

We also know that lb-in/s...Equation 1

Now, to find the power delivered in horsepower (hp), we will have to convert the Equation 1 to it's equivalent is hp.

Now, we know that 1 lb-in/s= hp

Therefore, 628320 lb-in/s= HP

Thus, the required answer in HP is 95.2 HP.

the answer would be c:   ax + b = ax + c

step-by-step explanation: