Compare and order 5.2, -5.6, 3 9/10, the square root of 21? ?

I would first suggest turning them all to one thing, like all decimals, or fractions. I chose decimals.

5.2, -5.6, 3.9, √21. To solve the square root, you have to simplify it. There is the square root of 3, times the square root of 7 which gets 21. These can't be simplified, so we can't simplify through that. But, the closest whole number that is a square root is 16. You can check by multiplying the same number together twice. Doing this will get you about 4.58

5.2, -5.6, 3.9, and ≈ 4.58. This is a simple ordering problem now.

It ends up as -5.6, 3 9/10, √21, 5.2

There are 2 decimals, one negative. There is one square root, and one mixed number. The square root is an infinite decimal when simplified

Hope this helps! ~Malachi

146%

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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