Arooms floor is y meters long. it’s width is 5 meters shorter. if the perimeter of the floor is (4y + 1) meters, can you solve for its length?

The question says that the length of the floor of a room is 'y' meters.

Its width is 5 meters shorter than the length,

If the width is 5 meters shorter than the actual width should be:

meters

Now the room is in the shape of a rectangle, so we will use the formula of the perimeter of a rectangle:

Perimeter =

The length of the floor is 'y' meters

The width of the floor is 'y-5' meters

Plugging the values of length and width we get,

Question says that the perimeter of the rectangle is meters.

So,

We will solve for 'y'.

Since,

The system of equation seems to have no solution.

Hence, no such floor exists.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.