I’m not even gonna pretend to know what to do, me

Choice A) max = 56, min = 9

Explanation:

With linear programming problems like this, the idea is to plot the feasible region, determine the vertices, and use them to figure out which vertex leads to the min and which vertex leads to the max.

Luckily, the first two steps of finding the diagram and vertices have been done for us already. At this point, all you need to do is plug in each vertex one at a time into the objective function z = 3x+5y

The vertex points, or corner points, are: (0,7),(7,7),(7,3),(3,0), and (0,3)

We'll plug them in one at a time. Then we'll see which z value is the smallest and which is the largest

Plug in (x,y) = (0,7)

z =  3x+5y

z =  3(0)+5(7)

z = 0+35

z = 35

Plug in (x,y) = (7,7)

z =  3x+5y

z =  3(7)+5(7)

z = 21+35

z = 56

Plug in (x,y) = (7,3)

z =  3x+5y

z =  3(7)+5(3)

z = 21+15

z = 36

Plug in (x,y) = (3,0)

z =  3x+5y

z =  3(3)+5(0)

z = 9+0

z = 9

Plug in (x,y) = (0,3)

z =  3x+5y

z =  3(0)+5(3)

z = 0+15

z = 15

Summary:

The largest z value we got was z = 56, so this is the max value. It occurs at (x,y) = (7,7)

The smallest z value we got was z = 9, so this is the min value. It occurs at (x,y) = (3,0)

So that's why the final answer is choice A

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)