If m is the midpoint of line ab, then m is between a and b and am=mb. converse: bioconditional

given: m is the midpoint of line ab

postulate 5: a midpoint of a line segment is the halfway point either end point of the line.

m is between a and b

so, am=mb

to proof=

as given m is the midpoint of line ab.

definition of the mid point

a point on a line segment that divides it into two equal parts

as shown in the diagram given below.

am =

mb =

thus

am = mb

hence proved

now bioconditional

given: m is between a and b,   am=mb

prove that m is the midpoint of line ab.

to proof

ab = am + mb

( as given am = mb)

put in the above equation

ab = 2am

i.e m is the point divided ab in two equal parts.

by definition of the mid point

m is the mid point of ab.

hence proved

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752