Find two consecutive even integers such that twice the smaller is 16 more than the larger

n, n + 2 - two consecutive even integers

2n = (n + 2) - 16

2n = n + 2 - 16

2n = n - 14       |subtract n from both sides

n = -14

n + 2 = -14 + 2 = -12

-14, -12.

5

step-by-step explanation: