The equation of the line that goes through the points (−6,2) and (-7,-7) can be written in general form ax+by+c=0 where a= ? b=? ? c=? someone me find a b c

A = 9, B = - 1, C= 56

obtain the equation in ' slope-intercept form'

y = mx + c → ( m is the slope and c the y- intercept)

calculate m using the ' gradient formula'

m = (- 7 - 2)/(- 7 + 6) = (-9)/(-1) = 9

partial equation is y = 9x + c

to find c substitute either of the 2 points into the equation.

using (- 6, 2) then

2 = - 54 + c ⇒ c = 2 + 54 = 56

y = 9x + 56 → slope-intercept equation

subtract y from both sides

0 = 9x - y + 56 → general form

with A = 9, B = - 1, C = 56

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step-by-step explanation:

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: