Mathematics, 09.07.2019 04:30, arielcainess

6. mike and his best friend dan have the same birthday, but mike is three years older than dan. let the variable x represent mike's age and y represent dan's age. which graph represents the relationship between dan's age and mike's age? also can anyone tell me all the answers for solving equations unit test i really need the .

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answered: lovemelikeajew

it is given that mike and his best friend dan have the same birthday.

mike's age =x

dan's age = y

but mike is three years older than dan.

so, mike being elder.we have to make equation in such a way that left hand side and right hand side of the equation becomes equal.the equation becomes

a.t.q

x=y+3

as you have not written anyone's age so if either mike's age or dan's age is given.

by substituting anyone's age in the equation you can find the age of other.

to draw the graph of x=y+3

x-y=3

take different positive values of (x,y) like (20,17), (25,,53)⇒ i have taken these values because it represent ages. to draw the graph you can take negative value of x and y also.

to draw the graph you only need two points.and every point on the graph will satisfy this equation.

as this equation is of two variable you need two different equation's in x and y to get values of x and y.

answered: Guest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

answered: Guest

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?