Mrs. mcalister wrote the equation 10t-4t+3t=8 on the board and asked students to write an equivalent equation. the table below shows the responses from four students. student responses name 1.michele 2.piotr 3.ronnie 4.tanisha equation 1.3t=8 2.6t=8 3.-1t=8 4.9t=8 which student wrote an equation that is equivalent to mrs. mcalister’s? michele piotr ronnie tanisha

Tanisha wrote an equation that is same as Mrs. McAlister's equation.

9t = 8

Step-by-step explanation:

Mrs. McAlister wrote an equation on the board is:

10t-4t+3t=8

Now we simplify this

In order to simplify the left side, we combine like terms.

Here 10t, -4t, & 3t are like terms

So, 10t - 4t + 3t is equivalent to 9t

Thus,

9t = 8

This equation is written by the Tanisha.

That's the final answer.

I hope it helps you.

d? maybe

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2