Tom quig traveled  240  miles east of st. louis. for most of the trip he averaged  60  mph, but for one period of time he was slowed to  20  mph due to a major accident. if the total time of travel was  6  hours, how many miles did he drive at the reduced speed?

Tom Quig traveled 280 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time he was slowed to 10 mph due to a major accident. If the total time of travel was 8 hours, how many miles did he drive at the reduced speed?

.

You will need to apply the "distance formula":

d = rt

where

d is distance

r is rate or speed

t is time

.

Let x = time driving at reduced speed

then

8-x = time driving at 60 mph

.

60(8-x) + 10x = 280

480 - 60x + 10x = 280

480 - 50x = 280

480 = 50x + 280

200 = 50x

4 hours = x

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This means he spent 4 hours driving at 10 mph, the distance he drove at this rate then is:

4 * 10 = 40 miles

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following