Consider f(x) = bx. which statement(s) are true for 0 < b < 1? check all that apply: the domain is all real numbers. the domain is x > 0. the range is all real numbers. the range is y > 0. the graph has x-intercept 1. the graph has a y-intercept of 1. the function is always increasing. the function is always decreasing.

we are given

where 0<b<1

Domain:

domain is all possible values of x for which any function is defined

so, we can select any values of x for which function

it will be defined for all real x

so, domain is

Range:

Range is all possible values of y for which x is defined

we are given that b is positive

so, value of function will always be positive

so, range is

or

y>0

x-intercept:

we can set f(x)=0

and then we can solve for x

x is undefined

so, x-intercept does not exist

Increasing or decreasing:

Since, 0<b<1

so, b is positive value less than 1

so, as we increase value of , b^x will keep decreasing

so, this is decreasing

The true statements about the function are:

The function is given as:

There is no restriction on the values of x.

So, the domain of the function is: (a) the set of all real numbers

means that, the smallest value of the function will be greater than  0, and the function will not cross the x-axis

So, the range of the function is: (d) y > 0, and the graph has no x-intercept

also means that the value of b is a positive number less than 1.

So, as x increases, f(x) decreases

In other words, (h) the function is always decreasing.

Hence, the true statements about the function are: (a), (d) and (h)

Read more about functions at:

link

hdjd

step-by-step explanation:

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step-by-step explanation:

$54.99 includes 500 min. if she does not exceed 500 min then her bill is $54.99