The length of the segment ad is 28 cm. the distance between the midpoints of segments ab and cd is 16 cm. find the length of the segment bc .

Given=

length of the segment AD is 28 cm

distance between the midpoints of segments AB and CD is 16 cm

find out length of BC

To proof

AD = 28 cm

let the midpoint of the AB is E.

let the midpoint of the CD is F.

E & F are the midpoints i.e these points divide AB & CD in two equal parts.

Let BC = z

Let AE = EB = x     ( E is midpoint)

Let CF = FD = y      (F is midpoint)

the equation becomes

2x + 2y + z = 28

x + y + z = 16

mulitipy above equation by 2

we  get

2x + 2y + 2z = 32

thus solving the equations

2x + 2y + 2z = 32

2x + 2y + z = 28

we get

z = 4 cm

i.e BC = 4 cm

Hence proved

can you complete your sentence? i could !

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!