Calculate the cross product assuming that u × w = 0, 1, 3 . (2u + 3w) × w

Answer- (2u + 3w) × w =  < 0, 2, 6 >

Solution -

Given in the problem

(u × w) = < 0, 1, 3 >

Then,

(2u + 3w) × w = (2u × w) + (3w × w)

(2u × w) = 2(u × w) = < 0×2, 1×2, 3×2 > = < 0, 2, 6 >  ( ∵ Multiplying it by 3 with all components)

(3w × w) = 3(w × w) = 0                                               ( ∵ The cross product of any vector with itself is 0)

∴ (2u + 3w) × w =  < 0, 2, 6 >

the answer will be b x² +x-1

step-by-step explanation: