Jamar rolls a 1-6 number cube three times. what is the probability he will roll an even number, then a 6, then a 4?

there is 2, 4, and 6. you have 3/6 chances of rolling even in one roll.  you have 9/18 chances to roll an even number. this is because there are 18 possible outcomes, 6 times 3, and 3 times 3. to roll a six you have 1/6 chances for one roll, miltiply it again and you get 3/18 chances to roll a six. you also have 3/18 chances to roll a 4.

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: