What is the coefficient of

To expand any binomial of this kind, first write a^5, the first term.  

The coefficient of this term is 1 and it is the first term. The

coefficient of the second term (which has a^4 and (2b)^1 in it) is the

exponent of a in the first term times the existing coefficient (1),

divided by the number of the term. So, the coefficient of the second

term is 5*1/1 = 5.

Okay, so now we have:

  a^5 + 5*a^4*(2b)^1

To get the coefficient of the third term, apply the same rule. Take

the exponent of a in the second term, multiply by the coeffcient of

the second term and divide by the number of the term. So, 4*5/2 = 10.  

Now we have:

  a^5 + 5*a^4*(2b)^1 + 10*a^3*(2b)^2

Next, 3*10/3 = 10:

  a^5 + 5*a^4*(2b)^1 + 10*a^3*(2b)^2 + 10*a^2*(2b)^3

Next, 2*10/4 = 5, and so on.

i think the answer is b)

step-by-step explanation:

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step-by-step explanation: vsfdvsfvd