Solve for p. 2p+3> 2(p−3) all real numbers p> −9 no solution p> −3

Hi,

All Real Numbers

This can be achieved in 7 easy steps!

My Numerical work:

1. 2p + 3 > 2(p - 3)

Simplify both sides of the inequality:

2. 2p + 3 > 2p - 6

Subtract 2p from both sides:

3. 20 +3 - 20> 2p - 6 - 2p

4. 3 > -6

Subtract 3 from both sides:

5. 3 -3 > -6 - 2p

6. 0 > -9

7. All real numbers are solutions.

I Hope I Helped!

Solve for p.

First, distribute 2 to all terms within the parenthesis

2(p−3) = 2(p) + 2(-3) = 2p - 6

2p+3 > 2p - 6

Isolate the p. Subtract p from both sides, and subtract 3 from both sides

2p (-2p) + 3 (-3) > 2p (-2p) - 6 (-3)

2p - 2p > -6 - 3

Simplify.

0 > - 9

0 > -9

all real numbers is your answer

hope this helps

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted