Tonya dog- walking service charges a flat rate of $20 per month, plus $3 per mile that each dog is walked. beth does not charge a monthly fee for her dog- walking service , but she charges $5 per mile that each dog is walked. find the miles for which tonya and beth will charge the same amount.

Given that Tonya charges 20$ monthly fee and 3$ per mile of her dog-walking service.

And Beth does not charge any monthly fee but charges 5$ per mile of the dog walked in.

Let x be the number of miles dog has walked in a month.

The amount Tonya will charge on x miles = fixed monthly fee + number of miles * charge per mile = 20+3x

And the amount Beth will charge on x miles = 0+ 5*x = 5x.

We are asked to find the x-value for which Beth chargeable amount = Tonya chargeable amount

That is 5x = 20+3x

            5x-2x = 20

              2x=20

                x=

Hence number of miles for which Tonya and Beth will charge the same amount is 10.

gaddgad

step-by-step explanation:

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: