Mathematics, 09.07.2019 22:30, nana54muller
In segment addition how do i find x when de = x - 2, ef = x + 5, and df = 9
Answers: 1
![\bf D\underset{\leftarrow DF=9\to \qquad }{\stackrel{x-2}{\rule[0.35em]{10em}{0.25pt}}E\stackrel{x+5}{\rule[0.35em]{15em}{0.25pt}}}F \\\\\\ DF=DE+EF\implies \stackrel{DF}{9}=\stackrel{DE}{(x-2)}+\stackrel{EF}{(x+5)}\implies 9=2x+3 \\\\\\ 6=2x\implies \cfrac{6}{2}=x\implies 3=x](/tpl/images/0071/0226/6b76c.png)
Other questions on the subject: Mathematics
Mathematics, 21.06.2019 19:30, shay03littletop5kx2p
Simplify (1/2)4th power a. (1/16) b.(1/8) c.(1/4)
Answers: 2
Do you know the correct answer?
In segment addition how do i find x when de = x - 2, ef = x + 5, and df = 9...
Questions in other subjects:
Mathematics, 16.07.2019 20:00
Mathematics, 16.07.2019 20:00
Chemistry, 16.07.2019 20:00
Mathematics, 16.07.2019 20:00
Chemistry, 16.07.2019 20:00
Mathematics, 16.07.2019 20:00
Health, 16.07.2019 20:00
Business, 16.07.2019 20:00
