Mathematics, 09.07.2019 23:00, nurikchan
Find f '(x) for f(x) = squaroot cos (6x) find dy/dx of y = csc squareroot x
Answers: 1
![\bf f(x)=\sqrt{cos(6x)}\implies f(x)=[cos(6x)]^{\frac{1}{2}} \\\\\\ f'(x)=\stackrel{\textit{using the chain-rule}}{\cfrac{1}{2}[cos(6x)]^{-\frac{1}{2}}~\cdot ~-sin(6x)~\cdot ~6}\implies f'(x)=\cfrac{-6sin(6x)}{2[cos(6x)]^{\frac{1}{2}}} \\\\\\ f'(x)=\cfrac{-3sin(6x)}{\sqrt{cos(6x)}} \\\\[-0.35em] \rule{34em}{0.25pt}](/tpl/images/0071/1020/fe287.png)
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Find f '(x) for f(x) = squaroot cos (6x) find dy/dx of y = csc squareroot x...
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