Mathematics, 10.07.2019 02:30, genyjoannerubiera
Solve this linear system using determinants: 2x + 3y = 6 −8x − 3y = 12 |a| = |ax| = |ay| =
Answers: 1
![\left\{\begin{array}{ccc}2x+3y=6\\-8x-3y=12\end{array}\right\\\\A=\left[\begin{array}{ccc}2&3\\-8&-3\end{array}\right] \\\\|A|=\left|\begin{array}{ccc}2&3\\-8&-3\end{array}\right|=(2)(-3)-(-8)(3)=-6+24=18\\\\|A_x|=\left|\begin{array}{ccc}6&3\\12&-3\end{array}\right|=(6)(-3)-(12)(3)=-18-36=-54\\\\|A_y|=\left|\begin{array}{ccc}2&6\\-8&12\end{array}\right|=(2)(12)-(-8)(6)=24+48=72\\\\x=\dfrac{|A_x|}{|A|}=\dfrac{-54}{18}=-3\\\\y=\dfrac{|A_y|}{|A|}=\dfrac{72}{18}=4\\\\\ x=4,\ y=-3](/tpl/images/0071/6468/088a1.png)
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Solve this linear system using determinants: 2x + 3y = 6 −8x − 3y = 12 |a| = |ax| = |ay| =...
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