Flynn opens a saving account. in one 3 month period, he makes deposit of $75.50 and $55.25. he makes withdrawal of $25.15 and $18.65. his balance at the end of the 3 month period is $210.85. explain how you can find his initial deposit amount?

X=initial deposit amount.
we have to add to the initial deposit amount the incomes and subtract the withdrawal
x+($75.5+$55.25)-($25.15+$18.65)=$210.85
Now we solve this equation.
x+$130.75-$43.8=$210.85
x+$86.95=$210.85
x=$210.85-$86.95
x=$123.9

his initial deposit amount is $123.9