Community sports complex being built in oak valley. perimeter of the rectangular playing field is 542 yards. length of the field is 9 yards less than quadruple the width. what are the dimensions of the playing field

Perimeter of field = 542 yards

Let the width of the field be x.

As given in the question, length of the field is 9 yards less than quadruple the width.

So, length = (4x - 9) yards

We know that perimeter of a rectangle is given as:

Perimeter = 2 (length + width)

542 = 2 (x + 4x - 9)

271 = 5x - 9

5x = 280

x = 280 / 5

x = 56

Hence, width of field = 56 yards

Length of field = 4x - 9

= 4*56 - 9

= 215 yards

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