(grade 8 work- a grade work)q = solve these pair of simultaneous equations : pleassse me i've been doing this homework for 5 hours and 16 !

It can work well to equate the expressions for y, then put the quadratic into standard form and solve in any of the ways you've been taught.

... x² -2x = 2x -3

... x² -4x +3 = 0

... (x -1)(x -3) = 0 . . . . . . . . factor. Choose factors of 3 that sum to -4: {-1, -3}.

By the zero-product rule, the product can only be zero if one or more factors is zero.

First factor:

... x -1 = 0

... x = 1 . . . . . . add 1

Second factor:

... x -3 = 0

... x = 3 . . . . . . add 3

The solutions for x are 1 and 3. The corresponding solutions for y are ...

... 2x -3 = 2·1 -3 = -1

... 2x -3 = 2·3 -3 = 3

Soutions to these equations are

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)