< 1 and < 2 are supplementary angles. m < 1 is 4y+7, and m< 2 is 9y+4. find m< 2.

Supplementary angles are angles that add to 180°. Given that and are supplementary angles, we can say that the measures of the two angles add to 180°, as shown below:

The problem also gave us values for and , which we can substitute into the equation we found in the last step, as shown below:

We have found that y = 13. We can use this to find by "plugging in" the 13 for y:

The measure of angle 2, is 121°.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )