I'm studying for a huge test, and this question makes no sense! i will give brainliest to anyone who can give me the correct answer, and explain it to me. -four times the first of three consecutive even integers is six more than the product of two and the third integer. find the integers.

2n,2n+2,2n+4 - three consecutive even integers

So, it turns those are ODD integers: 7,9,11

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square