How many five-digit numbers are there that do not have two consecutive digits the same? for example, you would count 12104 and 12397 but not 6321 (it is not five digits) or 43356 (it has two consecutive 3s). scheinerman, edward a.. mathematics: a discrete introduction (page 39). cengage textbook. kindle edition?

We can choose the first digit in any of 9 ways, 1,2,3,4,5,6,7,9 or 9 .

We can then choose the second digit in any of the 9 ways, 0 or any of 8 ways not chosen for the first digit.

We can then choose the third digit in any of the 9 ways, other than the second digit.

We can choose the fourth digit in any of the 9 ways, other than the third digit.

And we can choose the fifth digit in any of the 9 ways, other than fourth digit.

Hence number of ways = 9*9*9*9*9 =

So, total number of five digit numbers which don't have consecutive digits same is 59049.

part a

in a city ice cream is mostly only bought when the temperature is very high as ice cream cools down our

so we can derive the conclusion that as the temperature increases the number of ice creams sold also increases

part b

y intercept is 5

slope is 2

happy to

pls mark as brainliest

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,