Wendy took a trip from one city to another, a distance of 500 mi. she traveled part of the way by bus, which arrived at the train station just in time for wendy to complete her journey by train. the bus averaged 40 mi/h, and the train averaged 120 mi/h. the entire trip took 6 1 2 h. how long did wendy spend on the train?

Answer- Wendy spent 3 hours on the train

Solution-

The distance between the cities= 500 mi.

She traveled part of the way by bus, and other part by train.

The bus averaged 40 mph, and the train averaged 120 mph.

The entire trip took 6.5 hours.

let d = distance traveled by train

the total distance was given as 500 mi ,

therefore, distance traveled by bus  = (500-d) mi

time = distance/speed

⇒ train traveling time + bus traveling time = 6.5 hrs

⇒

⇒ d + 3(500-d) = 120(6.5)

⇒ d + 1500 - 3d = 780

⇒ 2d = 720

⇒ d = 360  mi

so d = 360 mi by train

⇒ 360/120 = 3 hrs on the train

answer: the 4 kilogram bag

step-by-step explanation: this is because if you divide the number of kilograms into the total it will tell you how much each individual kilogram would be worth. 2 kilos is 7 and change 3 would be around 6 ish and the 4 kilo would be 4.6 and change and the 5 kilos would be like 4.88

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2