Consider the functions f(x)=3x^2 - 5 and g(x)= √x -5 +2 how can i find f(5) g(5) f(4) g(4) describe the domain of f(x) describe the domain of g(x) why is the domain of one of these functions more restructive than the other?

F(5):

G(5):

F(4):

G(4):

Hope it helped,

BioTeacher101

f(x) = 3x² - 5      

f(5) = 3(5)² - 5   →   f(5) = 3(25) - 5   →   f(5) = 75 - 5   →   f(5) = 70

f(4) = 3(4)² - 5   →   f(4) = 3(16) - 5   →   f(4) = 48 - 5   →   f(5) = 43

DOMAIN of f(x): All real numbers (because there are no restrictions on "x")

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g(x) = + 2

g(5) = + 2  →  g(5) =   + 2   →   g(5) = 2

g(4) = + 2   →  g(4) =   + 2   →   g(4) = no real solutions

DOMAIN of g(x): x ≥ 5    (because you cannot take the square root of a negative number)

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

answer: c i think

step-by-step explanation: